Joey LIU | NANTSOU


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/**
 * It's a dynamic programming problems.
 * big O is n squared.
 */
class Solution {
    public boolean wordBreak(String s, List<String> wordDict) {
        boolean[] dp = new boolean[s.length() + 1];
        dp[0] = true;
        for (int i = 0; i < dp.length; i++) {
            for (int j = i - 1; j >= 0; j--) {
                if (dp[j] && wordDict.contains(s.substring(j, i))) {
                    dp[i] = true;
                    break;
                }
            }
        }
        return dp[dp.length - 1];
    }
}